(5c^2-4)(2c^2+c-3)=0

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Solution for (5c^2-4)(2c^2+c-3)=0 equation:


Simplifying
(5c2 + -4)(2c2 + c + -3) = 0

Reorder the terms:
(-4 + 5c2)(2c2 + c + -3) = 0

Reorder the terms:
(-4 + 5c2)(-3 + c + 2c2) = 0

Multiply (-4 + 5c2) * (-3 + c + 2c2)
(-4(-3 + c + 2c2) + 5c2 * (-3 + c + 2c2)) = 0
((-3 * -4 + c * -4 + 2c2 * -4) + 5c2 * (-3 + c + 2c2)) = 0
((12 + -4c + -8c2) + 5c2 * (-3 + c + 2c2)) = 0
(12 + -4c + -8c2 + (-3 * 5c2 + c * 5c2 + 2c2 * 5c2)) = 0
(12 + -4c + -8c2 + (-15c2 + 5c3 + 10c4)) = 0

Combine like terms: -8c2 + -15c2 = -23c2
(12 + -4c + -23c2 + 5c3 + 10c4) = 0

Solving
12 + -4c + -23c2 + 5c3 + 10c4 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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